w^2+3w-30.24=0

Solution for w^2+3w-30.24=0 equation:

w^2+3w-30.24=0

a = 1; b = 3; c = -30.24;
Δ = b2-4ac
Δ = 32-4·1·(-30.24)
Δ = 129.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129.96}}{2*1}=\frac{-3-\sqrt{129.96}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129.96}}{2*1}=\frac{-3+\sqrt{129.96}}{2}
$